A spring with a 6-kg mass and a damping constant 13 can be held stretched 1.5 meters beyond its natural length by a force of 4.5 newtons. Suppose the spring is stretched 3 meters beyond its natural length and then released with zero velocity. In the notation of the text, what is the value b^2 - 4mk? Find the position of the mass, in meters, after t seconds. Your answer should be a function of the variable t of the form c1e^at + c2e^bt where a = (the larger of the two) b = (the smaller of the two) c1 = c2 =