A spring with a 7-kg mass and a damping constant 7 can be held stretched 1 meters beyond its natural length by a force of 4 newtons. Suppose the spring is stretched 2 meters beyond its natural length and then released with zero velocity, In the notation of the text, what is the value c^2 - 4mk? m^2kg^2/sec^2 Find the position of the mass, in meters, after t seconds. Your answer should be a function of the variable t with the general form c1e^{?t} cos(?t) + c2e^{?t} sin(?t) ? = ? = ? = ? = c1 = c2 =
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We are given that a force of F newtons can hold the spring stretched x meters beyond its natural length. According to Hooke's law, F = kx, where k is the spring constant. Show more…
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