Question

(1 point) A tank contains 80 kg of salt and 1000 L of water. A solution of a concentration 0.04 kg of salt per liter enters a tank at the rate 10 L/min. The solution is mixed and drains from the tank at the same rate. a.) What is the concentration of our solution in the tank initially? concentration = 80/1000 (kg/L) b.) Find the amount of salt in the tank after 3.5 hours. amount = 40+40e^(-210/125) (kg) c.) Find the concentration of salt in the solution in the tank as time approaches infinity. concentration = 40/1000 (kg/L)

          (1 point) A tank contains 80 kg of salt and 1000 L of water. A solution of a concentration 0.04 kg of salt per liter enters a tank at the rate 10 L/min. The solution is mixed and drains from the tank at the same rate.

a.) What is the concentration of our solution in the tank initially?

concentration = 80/1000 (kg/L)

b.) Find the amount of salt in the tank after 3.5 hours.

amount = 40+40e^(-210/125) (kg)

c.) Find the concentration of salt in the solution in the tank as time approaches infinity.

concentration = 40/1000 (kg/L)

(1 point) A tank contains 80 kg of salt and 1000 L of water. A solution of a concentration 0.04 kg of salt per liter enters a tank at the rate 10 L/min. The solution is mixed and drains from the tank at the same rate.

a.) What is the concentration of our solution in the tank initially?

concentration = 80/1000 (kg/L)

b.) Find the amount of salt in the tank after 3.5 hours.

amount = 40+40e^(-210/125) (kg)

c.) Find the concentration of salt in the solution in the tank as time approaches infinity.

concentration = 40/1000 (kg/L)

Added by Veronica O.

Calculus: Early Transcendentals

James Stewart 8th Edition

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Solved by Expert Madhur L

06/03/2022

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a.) What is the concentration of the solution in the tank initially? concentration = 80/1000 (kg/L) b.) Find the amount of salt in the tank after 3.5 hours. amount = 40+40e^(-210/125) (kg) c.) Find the concentration of salt in the solution in the tank as time approaches infinity. concentration = 40/1000 (kg/L)