Find the total field force at (0, 0, 5) m due to Q1 = 0.35 ?C at (0, 4, 0) m and Q2 = -0.55 ?C at (3, 0, 0) m
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Given: q1 = 50 uC = 50 x 10^-6 C q2 = -25 uC = -25 x 10^-6 C r = 1.0 m Using the formula for electric field due to a point charge: E1 = k * q1 / r^2 E2 = k * q2 / r^2 where k is the Coulomb's constant = 9 x 10^9 Nm^2/C^2 Substitute the values: E1 = (9 x 10^9) Show more…
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