(1 point) Consider $f(x) = 1 - e^x$. A. Find the slope of the graph of $f(x)$ at the point where the graph crosses the x-axis. slope = -1 B. Find the equation of the tangent line to the curve at this point. y = -x C. Find the equation of the line perpendicular to the tangent line at this point. (This is called the normal line.) y =
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The derivative represents the rate of change of the function at any given point. B. Once we have the slope of the graph at that point, we can use the point-slope form of a line to find the equation of the tangent line. The point-slope form is given by y - y1 = Show more…
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