00:01
In this question, we are given parametric equation of line 1.
00:06
X is equals to negative 24 plus t.
00:13
Y is equals to negative 10 plus 2t.
00:18
Z is equals to 34 negative 5t.
00:21
We are given line 2, which is x is equals to 5 negative 2t.
00:29
Y is equals to 12 negative 2t.
00:33
Z is equals to 27 negative 70.
00:35
We have to find the intersection point of the acute angle.
00:45
So let us say that as theta.
00:49
So first let us equate l1 is equals to l2.
00:54
So we get negative 24 plus 3t.
00:58
Sorry, this is 3t is equals to l2.
01:03
We have 5 negative 2t.
01:07
So solving this, we get 5t is equals to 29.
01:11
Therefore, t is equals to 29 over 5, which implies t is equals to 5 .8.
01:22
So now substituting this, this is for x.
01:29
And similarly for y, we have negative 10 plus 2t is equals to 12 minus 2t.
01:35
So therefore, this term becomes 4t is equals to 22.
01:41
T is equals to 22 over 4.
01:44
So we get t is equals to 5 .5.
01:49
So moving on to z, we have z as 34 negative 5t is equals to 27 negative 70.
02:01
So we have 2t is equals to 7...