Question

Consider the function y = g(x) = -x^2 + 7x + 1. (a) Use the limit definition to compute a formula for y = g'(x). y = -2x+7 (b) Determine the slope of the tangent line to y = g(x) at the value x = 5. slope = -3 (c) Compute g(5). g(5) = (d) The equation for the tangent line to y = g(x) at the point (5, g(5)), written in point-slope form, is y - 76 = -3 (x - 5) Fill in the blanks with the appropriate numbers.

          Consider the function y = g(x) = -x^2 + 7x + 1.
(a) Use the limit definition to compute a formula for y = g'(x).
y = -2x+7
(b) Determine the slope of the tangent line to y = g(x) at the value x = 5.
slope = -3
(c) Compute g(5).
g(5) =
(d) The equation for the tangent line to y = g(x) at the point (5, g(5)), written in point-slope form, is
y - 76 = -3 (x - 5)
Fill in the blanks with the appropriate numbers.
        
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Consider the function y = g(x) = -x^2 + 7x + 1.
(a) Use the limit definition to compute a formula for y = g'(x).
y = -2x+7
(b) Determine the slope of the tangent line to y = g(x) at the value x = 5.
slope = -3
(c) Compute g(5).
g(5) =
(d) The equation for the tangent line to y = g(x) at the point (5, g(5)), written in point-slope form, is
y - 76 = -3 (x - 5)
Fill in the blanks with the appropriate numbers.

Added by Shannon S.

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Calculus: Early Transcendentals
Calculus: Early Transcendentals
James Stewart 8th Edition
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Consider the function y = g(x) = -x^2 + 7x + 1. (a) Use the limit definition to compute a formula for y = g'(x). (b) Determine the slope of the tangent line to y = g(x) at the value x = 5. (c) Compute g(5). (d) The equation for the tangent line to y = g(x) at the point (5, g(5)), written in point-slope form. Fill in the blanks with the appropriate numbers.
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Transcript

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00:01 Hi there, so for this problem we are given the function y that we can also label as g of x, that is minus x squared plus 7 times x plus 1.
00:16 Now the question for part a is to determine the rate of change of this function, that is the derivative of this function that you already know is 2 times x plus 7.
00:31 Now for par b, we need to determine the slope of the tangent line to this function at the value x equals to 5.
00:40 So what we need to do is to simply evaluate the expression that we obtained from before at 5, so that will be minus 2 times 5, and this plus 7.
00:51 So this will give us a value of minus 3, as you already obtain.
00:59 Now for part c of this problem, we need to compute the, we need to evaluate the function g at 5, so that means substitute the value of 5 in here...
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