Question

Consider the line L(t) = <3t - 2, -5>. Then: L is parallel to the line <2 + t, 5 - 3t> L is perpendicular to the line <4, 6t - 1> L is neither to the line <3 + 3t, 5 + 3t> L is ? to the line <-4 - 6t, -2>

          Consider the line L(t) = <3t - 2, -5>. Then:
L is parallel to the line <2 + t, 5 - 3t>
L is perpendicular to the line <4, 6t - 1>
L is neither to the line <3 + 3t, 5 + 3t>
L is ? to the line <-4 - 6t, -2>

Added by Andrew C.

Calculus: Early Transcendentals

James Stewart 8th Edition

Instant Answer

Solved by Expert Adi S

11/26/2023

Step 1

The direction vector is given by the derivative of the parametric equations with respect to t: dL/dt = (d(3t - 2)/dt, d(-5)/dt) = (3, 0) Now, let's analyze each line: 1) Line (2 + t, 5 - 3t): The direction vector is (1, -3). To check if L is parallel to this Show more…

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Consider the line L(t) = <3t - 2, -5>. Then: L is parallel to the line <2 + t, 5 - 3t> L is perpendicular to the line <4, 6t - 1> L is neither to the line <3 + 3t, 5 + 3t> L is ? to the line <-4 - 6t, -2>