00:01
Here, we're given a limit as x approaches infinity of, for example, negative 4x divided by 9 plus 2x.
00:10
And we want to find this limit.
00:12
Well, what i would do is always divide by the highest power in the denominator.
00:17
So in this case, that's 1.
00:18
So i'm going to divide everything by x.
00:21
So i would get negative 4 divided by 9 over x plus 2 because everything got divided by x.
00:27
And then remember that as x goes to infinity, something divided by x goes to zero.
00:34
So really, this is zero.
00:36
So all that really matters in this case is negative 4 over 2, or simply negative 2.
00:42
And that's the way we're going to do all of these problems.
00:45
I will point out that there's a little bit of something different when we have a square root.
00:49
So let me do one of those.
00:51
Say we have the limit as x approaches infinity of the square root of x squared plus 6x over 7...