Express the following sum in closed form. sum_{k=1}^{n} (2+2 cdot frac{k}{n})^2 = Hint: Start by multiplying out (2+2 cdot frac{k}{n})^2. Note: Your answer should be in terms of n.
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Step 1: Rewrite the given sum as a series and expand it: \(2 + 2 \cdot k = 2 + 2 \cdot 1 + 2 + 2 \cdot 2 + 2 + 2 \cdot 3 + \ldots\) \(= 2 + 4 + 2 + 4 + 2 + 6 + \ldots\) Show more…
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