(1 point) Find bases for the column space, the row space, and the null space of matrix A. You should verify that the Rank-Nullity Theorem holds. An equivalent echelon form of matrix A is given to make your work easier. A = egin{bmatrix} 3 & 22 & 3 \ 2 & 1 & 0 \ -5 & -2 & 3 \ 2 & 7 & -1 \ -5 & 10 & 4 end{bmatrix} sim egin{bmatrix} 1 & 0 & 0 \ 0 & 1 & 0 \ 0 & 0 & 1 \ 0 & 0 & 0 \ 0 & 0 & 0 end{bmatrix} Basis for the column space of A is left{ egin{bmatrix} 1 \ 0 \ 0 \ 0 \ 0 end{bmatrix}, egin{bmatrix} 0 \ 1 \ 0 \ 0 \ 0 end{bmatrix}, egin{bmatrix} 0 \ 0 \ 1 \ 0 \ 0 end{bmatrix} ight} Basis for the row space of A is
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First, let's write down the given matrix A and its echelon form: Matrix A: $$ A = \begin{bmatrix} 3 & 2 & -5 & -2 & 2 & 7 & -5 & 10 \end{bmatrix} $$ Echelon form of A: $$ \begin{bmatrix} 1 & 0 & -\frac{5}{3} & -\frac{2}{3} & \frac{2}{3} & \frac{7}{3} & Show more…
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