Find the area of the region enclosed between y = 3 sin(x) and y = 4 cos(x) from x = 0 to x = 0.8?. Hint: Notice that this region consists of two parts.
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To do this, we set the two equations equal to each other: $3\sin(x) = 4\cos(x)$ Divide both sides by $\cos(x)$: $\frac{3\sin(x)}{\cos(x)} = 4$ Now, we can use the identity $\tan(x) = \frac{\sin(x)}{\cos(x)}$: $3\tan(x) = 4$ Solve for $x$: $x = Show more…
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