Find the inverse Laplace transform of F(s) = e^(-6s) / (s^2 - 2s - 8) f(t) = (Use step(t-c) for u_c(t) .)
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Step 1
First, we need to factor the denominator of F(s) to find its partial fraction decomposition: F(s) = (s-4)(s+2) F(s) = A/(s-4) + B/(s+2) Multiplying both sides by (s-4)(s+2), we get: s^2 - 2s - 8 = A(s+2) + B(s-4) Show more…
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