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Hello students in this question it is given that determinant of matrix a, b, c, one, one, d, e f is equal to minus 1 and determinant of matrix a, b, c, 1, 2, 3, d e f is equal to minus 5.
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For the a part, we have to find the determinant of a, b, c, 666, d e f.
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Taking 6 common, we have 6 multiply by determinant of a, b, c, 1 ,111, d, e, f.
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And this is equal to 6 multiply by minus 1, which is minus 6.
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Next, we have determinant of a, b, c, 6, 9, 12, d, e, f.
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This is equal to determinant of a, b, c.
00:57
Taking three common we have abc 2 3 4 d e f this is equal to 3 determinant of a b c this is 1 plus 1 this is 2 plus 1 and this is 3 plus 1 d e f we can split this determinant so we have 3 determinant of a b c 1 2 2 3 3 e .f plus determinant of a, b, c, one, one, one, d .e.
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F...