00:01
For instance, it is given that y y dash plus x equal to root of x square plus y square and y of phi equal to minus root 56.
00:13
So, using the substitution method, using the substitution u equal to x square plus y square.
00:29
So, now differentiating this term with respect to x, we get u dash equal to 2x plus 2y y dash.
00:42
So, now put this value in the original equation.
00:45
So, we get y dash divided by 2 minus x plus x which is equal to root u.
00:54
This one can be written as y y dash equal to u dash divided by 2 minus x.
01:03
So, which implies u dash divided by 2 equal to root u.
01:10
So, du divided by dx equal to 2 root u or it can be written as du divided by root u equal to 2 dx.
01:25
Now, integrate on both sides.
01:26
So, we get integral du divided by root u equal to integral 2 dx.
01:33
So, which is equal to u power 1 by 2 divided by 1 divided by 2 which is equal to 2x plus c...