Question

Suppose the point (6, -2) exists on the graph of y = f(x). Find the corresponding point on the graphs of the following transformations: (Express your answer as a coordinate (X, Y)). y = f(x - 1) + 3: y = 4f(1/3x): y = -4f(-3x) - 8: y = 2f(-(x - 7)): y = 3f(2(x - 4)) - 4: y = 3f(-4x - 6) - 2:

          Suppose the point (6, -2) exists on the graph of y = f(x).
Find the corresponding point on the graphs of the following transformations: (Express your answer as a coordinate (X, Y)).
y = f(x - 1) + 3:
y = 4f(1/3x):
y = -4f(-3x) - 8:
y = 2f(-(x - 7)):
y = 3f(2(x - 4)) - 4:
y = 3f(-4x - 6) - 2:

Suppose the point (6, -2) exists on the graph of y = f(x).
Find the corresponding point on the graphs of the following transformations: (Express your answer as a coordinate (X, Y)).
y = f(x - 1) + 3:
y = 4f(1/3x):
y = -4f(-3x) - 8:
y = 2f(-(x - 7)):
y = 3f(2(x - 4)) - 4:
y = 3f(-4x - 6) - 2:

Added by Guillermo C.

Calculus: Early Transcendentals

James Stewart 8th Edition

Instant Answer

Solved by Expert Andrew Noble

03/14/2023

Step 1

y = f(x - 1) + 3: Since the point (6, 2) exists on the graph of y = f(x), we can write 2 = f(6). Now, we need to find the corresponding point on the graph of y = f(x - 1) + 3. We can plug in x = 6 into the transformed equation: y = f(6 - 1) + 3 = f(5) + 3 Since 2 Show more…

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Suppose the point (6, -2) exists on the graph of y = f(x). Find the corresponding point on the graphs of the following transformations: (Express your answer as a coordinate (X,Y)). y = f(x - 1) + 3: y = 4f(1/3x): y = -4f(-3x) - 8: y = 2f(-(x - 7)): y = 3f(2(x - 4)) - 4: y = 3f(-4x - 6) - 2: