Question

The figure above shows a circuit containing an electromotive force (a battery), a capacitor with a capacitance of C farads (F), and a resistor with a resistance of R ohms (?). The voltage drop across the capacitor is Q/C, where Q is the charge (in coulombs), so in this case Kirchhoff's Law gives RI + Q/C = E(t). Since the current is I = dQ/dt, we have R(dQ/dt) + (1/C)Q = E(t). Suppose the resistance is 20 ?, the capacitance is 0.1F, a battery gives a constant voltage of E(t) = 30V, and the initial charge is Q(0) = 0C. Find the charge and the current at time t. Q(t) = I(t) =

          The figure above shows a circuit containing an electromotive force (a battery), a capacitor with a capacitance of C farads (F), and a resistor with a resistance of R ohms (?). The voltage drop across the capacitor is Q/C, where Q is the charge (in coulombs), so in this case Kirchhoff's Law gives
RI + Q/C = E(t).
Since the current is I = dQ/dt, we have
R(dQ/dt) + (1/C)Q = E(t).
Suppose the resistance is 20 ?, the capacitance is 0.1F, a battery gives a constant voltage of E(t) = 30V, and the initial charge is Q(0) = 0C.
Find the charge and the current at time t.
Q(t) =
I(t) =

The figure above shows a circuit containing an electromotive force (a battery), a capacitor with a capacitance of C farads (F), and a resistor with a resistance of R ohms (?). The voltage drop across the capacitor is Q/C, where Q is the charge (in coulombs), so in this case Kirchhoff's Law gives
RI + Q/C = E(t).
Since the current is I = dQ/dt, we have
R(dQ/dt) + (1/C)Q = E(t).
Suppose the resistance is 20 ?, the capacitance is 0.1F, a battery gives a constant voltage of E(t) = 30V, and the initial charge is Q(0) = 0C.
Find the charge and the current at time t.
Q(t) =
I(t) =

Added by Brenda D.

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