Question

Find the global minimum and maximum of the continuous function $f(x) = \frac{4}{x^2 + 1}$ on $[-1, 2]$.

Name: Find the global minimum and maximum of the continuous function f(x) = (4)/(x^2 + 1) on [-1, 2].
Uploaded: 2023-08-18T15:46:56-08:00
Duration: 1 min 11 s
Channel: Andrew Noble
Description: Find the global minimum and maximum of the continuous function f(x) = (4)/(x^2 + 1) on [-1, 2].

          Find the global minimum and maximum of the continuous function $f(x) = \frac{4}{x^2 + 1}$ on $[-1, 2]$.

Added by Beatriz D.

Calculus: Early Transcendentals

James Stewart 8th Edition

Instant Answer

Solved by Expert Andrew Noble

08/18/2023

Step 1

To find the critical points, we need to find where the derivative of the function is equal to zero or undefined. The derivative of f(x) is f'(x) = -8x/(x^2 + 1)^2. Setting f'(x) equal to zero, we get -8x/(x^2 + 1)^2 = 0. This implies that -8x = 0, which gives us x Show more…

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Points] Find the global minimum and maximum of the continuous function f(x)=(4)/(x^(2)+1) on -1,2. [-/8 Points] DETAILS 4 Find the global minimum and maximum of the continuous function f(x) on[-1,2].