Question

Poiscuille's Law. The speed of blood in a vessel is given by $$V(L, p, R, r, v)=\frac{p}{4 L v}\left(R^{2}-r^{2}\right)$$ where $R$ is the radius of the vessel, $r$ is the distance of the blood from the center of the vessel, $L$ is the length of the blood vessel, $p$ is the pressure, and $v$ is the viscosity. Find $V(1,100,0.0075,0.0025,0.05)$

          Poiscuille's Law. The speed of blood in a vessel is given by
$$V(L, p, R, r, v)=\frac{p}{4 L v}\left(R^{2}-r^{2}\right)$$
where $R$ is the radius of the vessel, $r$ is the distance of the blood from the center of the vessel, $L$ is the length of the blood vessel, $p$ is the pressure, and $v$ is the viscosity. Find $V(1,100,0.0075,0.0025,0.05)$

Added by Ronnie E.

Calculus: Early Transcendentals

James Stewart 8th Edition

Instant Answer

Solved by Expert Adi S

07/06/2024

Step 1

0075,0.0025,0.05)=\frac{100}{4\times 1\times 0.05}\left(0.0075^2-0.0025^2\right)$$ Show more…

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Poiscuille's Law. The speed of blood in a vessel is given by $$V(L, p, R, r, v)=\frac{p}{4 L v}\left(R^{2}-r^{2}\right)$$ where $R$ is the radius of the vessel, $r$ is the distance of the blood from the center of the vessel, $L$ is the length of the blood vessel, $p$ is the pressure, and $v$ is the viscosity. Find $V(1,100,0.0075,0.0025,0.05)$