Polar form of the complex number z = -1 + i?3 is a. z = 2(cos 5?/6 + i sin 5?/6) b. z = 2(cos 2?/3 + i sin 2?/3) c. z = 4(cos ?/6 - i sin ?/6) d. z = 4(cos 3?/6 + i sin 3?/6)
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The magnitude is given by the formula |z| = √(a^2 + b^2), where a and b are the real and imaginary parts of z, respectively. In this case, a = -1 and b = √3. |z| = √((-1)^2 + (√3)^2) = √(1 + 3) = √4 = 2 Show more…
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