Question

Popper Sec10_4 5. Find a parametrization $x = x(t)$, $y = y(t)$, $t in [0, 1]$ for the line segment from $(-1,5)$ to $(1,2)$. (a) $x(t) = 1 - 2t$, $y(t) = -3t + 5$ (b) $x(t) = 1 - 2t$, $y(t) = 3t + 2$ (c) $x(t) = 2t - 1$, $y(t) = -3t + 5$ (d) $x(t) = 2t - 1$, $y(t) = 3t + 2$ (e) none of these

          Popper Sec10_4
5. Find a parametrization $x = x(t)$, $y = y(t)$, $t in [0, 1]$ for the line
segment from $(-1,5)$ to $(1,2)$.
(a) $x(t) = 1 - 2t$, $y(t) = -3t + 5$
(b) $x(t) = 1 - 2t$, $y(t) = 3t + 2$
(c) $x(t) = 2t - 1$, $y(t) = -3t + 5$
(d) $x(t) = 2t - 1$, $y(t) = 3t + 2$
(e) none of these

Popper Sec104
5. Find a parametrization x = x(t), y = y(t), t in [0, 1] for the line
segment from (-1,5) to (1,2).
(a) x(t) = 1 - 2t, y(t) = -3t + 5
(b) x(t) = 1 - 2t, y(t) = 3t + 2
(c) x(t) = 2t - 1, y(t) = -3t + 5
(d) x(t) = 2t - 1, y(t) = 3t + 2
(e) none of these

Added by Nuria T.

Calculus: Early Transcendentals

James Stewart 8th Edition

Instant Answer

Solved by Expert Diogo Caetano

11/20/2022

Step 1

Step 1: Start with the given points (-1, 5) and (1, 2) and use the parametric equation of a line segment to find the parametrization. Show more…

Show all steps

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5. Find a parametrization x = x(t), y = y(t), t ∈ [0, 1] for the line segment from (-1, 5) to (1, 2). (a) x(t) = 1 - 2t, y(t) = -3t + 5 (b) x(t) = 1 - 2t, y(t) = 3t + 2 (c) x(t) = 2t - 1, y(t) = -3t + 5 (d) x(t) = 2t - 1, y(t) = 3t + 2 (e) none of these