Potassium sulfate is mixed with deionized water in a 400mL beaker to prepare a 175mL solution with concentration of 0.500M. A) How many moles of potassium sulfate are in the 175mL solution with a concentration of 0.500M? moles B) How many grams of potassium sulfate are in the 175mL solution with a concentration of 0.500M? grams
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500 M. Given: Volume of solution = 0.175 L Concentration of solution = 0.500 M Use the formula: \[ \text{moles} = \text{concentration} \times \text{volume} \] \[ \text{moles} = 0.500 \, \text{M} \times 0.175 \, \text{L} \] Show more…
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