Question

Potassium superoxide, KO2, reacts with water to produce oxygen and potassium hydroxide according to the following chemical equation. In a certain experiment, 30.00 g of potassium superoxide, KO2, reacted with an excess of water and 7.30 g of oxygen, O2, were isolated. (Molar masses: KO2 = 71.10 g/mol; O2 = 32.00 g/mol) 4 KO2(s) + 2 H2O(l) ? 3 O2(g) + 4 KOH(s) Calculate the theoretical yield of O2 in moles. a. 0.3165 mol b. 0.4481 mol c. 0.4212 mol d. 0.4520 mol

          Potassium superoxide, KO2, reacts with water to produce oxygen and potassium hydroxide according to the following chemical equation.
In a certain experiment, 30.00 g of potassium superoxide, KO2, reacted with an excess of water and 7.30 g of oxygen, O2, were isolated.
(Molar masses: KO2 = 71.10 g/mol; O2 = 32.00 g/mol)
4 KO2(s) + 2 H2O(l) ? 3 O2(g) + 4 KOH(s)
Calculate the theoretical yield of O2 in moles.
a. 0.3165 mol
b. 0.4481 mol
c. 0.4212 mol
d. 0.4520 mol

Potassium superoxide, KO2, reacts with water to produce oxygen and potassium hydroxide according to the following chemical equation.
In a certain experiment, 30.00 g of potassium superoxide, KO2, reacted with an excess of water and 7.30 g of oxygen, O2, were isolated.
(Molar masses: KO2 = 71.10 g/mol; O2 = 32.00 g/mol)
4 KO2(s) + 2 H2O(l) ? 3 O2(g) + 4 KOH(s)
Calculate the theoretical yield of O2 in moles.
a. 0.3165 mol
b. 0.4481 mol
c. 0.4212 mol
d. 0.4520 mol

Added by Tabitha R.

Chemistry: Structure and Properties

Nivaldo Tro 2nd Edition

Instant Answer

Solved by Expert Madhur L

05/09/2022

Step 1

00 g Molar mass of KO2 = 71.10 g/mol Number of moles of KO2 = Mass / Molar mass Number of moles of KO2 = 30.00 g / 71.10 g/mol Number of moles of KO2 = 0.4221 mol Show more…

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Potassium superoxide, KO2, reacts with water to produce oxygen and potassium hydroxide according to the following chemical equation. In a certain experiment, 30.00 g of potassium superoxide, KO2, reacted with an excess of water and 7.30 g of oxygen, O2, were isolated. (Molar masses: KO2 = 71.10 g/mol; O2 = 32.00 g/mol) 4 KO2(s) + 2 H2O(l) → 3 O2(g) + 4 KOH(s) Calculate the theoretical yield of O2 in moles. a. 0.3165 mol b. 0.4481 mol c. 0.4212 mol d. 0.4520 mol