power series ∫ ln(1 - x^2) dx
Added by Amit D.
Step 1
Let u = ln(1 + x^2) and dv = dx Then, du = (2x)/(1 + x^2) dx and v = x Using the integration by parts formula: ∫u dv = uv - ∫v du We get: ∫ln(1 + x^2) dx = x ln(1 + x^2) - ∫x * (2x/(1 + x^2)) dx ** Show more…
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