For CaCl2, the electrode reactions are:
Cathode: $Ca^{2+} + 2e^- \rightarrow Ca$
Anode: $2Cl^- \rightarrow Cl_2 + 2e^-$
Since 1 mole of Ca requires 2 moles of electrons, we can find the moles of electrons transferred during the electrolysis process.
We know
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