00:01
In this question we are given that the rectangular tank, rectangular tank having length which is 9 fit and breadth which is 4 fit and depth which is height also is 12 fit and its weight is equal to 60 per fit cube.
00:35
And here let's take a distance, take distance by any point from the top of the tank.
01:01
So we know that our force is a formula for force is equal to density multiplied by a volume.
01:18
So by using this formula we can find our force f is be the force.
01:22
So density is 60 multiplied by 9 multiplied by 4 and r volume of course will be as t5.
01:32
So together we will get here 2160 d1 by neutals and distance will be here distance will be as 12 minus y and that will be 12 minus y.
01:50
So therefore work done work done.
01:56
W will be equal to integration of a to b for f of tx.
02:02
So this is a pre -solution of the question and now let's move on to the first part of the question.
02:08
So in part one we need to find the work done of pumping, work done of pumping all of the liquid out over the top of time.
02:37
So, the weight will be as w is equal to integration of 0 to 12 for 2160 within the bracket 12 minus y d1 and this will be as 2160 within the bracket 12 by minus y, y square by 2 and our limits 0 to 12.
03:04
So when we put down here our limits will be our solution will be as 1 5 5...