00:01
Hello, in this question, in the first part, we will use the dilution equation.
00:09
So here, this dilution equation, we know that that is m1 v1, it is equal to m2 v2.
00:17
So here in this first part, we need to calculate this v1 value, initial value.
00:25
So therefore this will become n2 v2 divided by m1 here.
00:29
Here this m2 it is 3 .87 multiplied by 10 days to the power minus 6.
00:35
Multiply by v2 it is 50 ml.
00:38
It is there divided by here m1 it is 1 .94 multiplied by 10 days to the power minus 4.
00:45
M it is there and hence on solving this we will have this value that is 0 .9974 milliliter.
00:56
Now in case of second one again we need to find out the value of this v1.
01:01
Now we can directly put the value to this equation that is m2.
01:07
Here it is 9 .7 multiplied by 10 x to the power minus 6.
01:12
Multiply by v2 it is 50 ml divided by m1 here it is 1 .94 multiply by 10 x to the power minus 4.
01:20
And hence on solving this we will have that value that is 2 .5 ml of stock solution it is required.
01:31
Now in the third case, this initial volume, it will be m2 here it is 2 .91 multiply by 10 days to the power minus 5, multiply by v2 it is 50 ml divided by 1 .94 multiplied by 10 x to the power minus 4.
01:51
We are using these values from the table which are given in the question and hence on solving this we will have 7 .5 of the stock solution which is required here.
02:04
For the next part, it will be 3 .87 multiplied by 10 days to the power minus 5 multiplied by 50 ml divided by 1 .94 multiply by 10 days to the power minus 4m.
02:18
And hence on solving we will get the value that is 9 .974 ml it is required.
02:27
Now from the table 2 we see that that is red dye it absorbs the green color.
02:39
It absorbs green color.
02:45
So the wavelength of the green color it is between 5 .05 to 5 5 to 5 5 5 5 .5 nanometer it is there.
02:54
So therefore here we can say the range of wavelength needed to investigate...