00:01
Hello students in the question we have been asked to predict the major organic product of the reaction.
00:05
So the solution for this question is that in the first four reactions alken acts as a nucleophile and adds electrons to the sigma orbital of hvr bond.
00:40
Now first the alkyene is protonated at the the carbon with more number of hydrogen, more number of hydrogen atoms.
01:01
Then the nucleophile attacks the carbocatine to form the stable seti product.
01:25
In the fourth reaction, rearrangement of carbocotene takes the takes place to give a more stable tertiary carbocotene.
01:55
The reaction is addition hbr.
02:08
This electron shifts here and this comes over here and this will form the positive charge and here it is br negative.
02:24
This will come over here and it will form br.
02:32
Now in the second step we have c double bond c h cs3 h cs3 addition hbr where this shift over here this bond comes over here so it forms c h c h c s 3 single bond carvocatan positive h cs3 and there comes the br negative and thus it forms cs2, cs3, c, c, c, h, c s3, br.
03:16
Now in the third reaction we have addition hcl...