00:01
In this question we have equation that is 2 within the root multiplied by x plus y plus 2 z is equal to 6.
00:12
So this is as root 2 y minus 3 z is equal to under root 2 and therefore minus y plus root 2 z will be equal to minus 2.
00:29
So now we will find here ongumented matrix from these values, matrix and our matrix will be as root 2 1 2.
00:48
The next row will be a 0 root 2 minus 3 then we have 0 minus 1 root 2 and this matrix will be multiplied by it.
00:58
The values over here 6, 2 root 2 and minus 2.
01:06
So when we calculate as for the rule, r1 as r1 plus r3 and secondly for root 3, and secondly for root 3 which is root 2 multiplied by r3 plus r2.
01:21
So we will get here our matrix as root 2, 0 plus root 2.
01:31
Next row will be as 0 root 2 minus 3 and next is 0 minus 1.
01:41
And here we will get 4 to root 2 and 0.
01:48
So again we will use r1 will be as tense r1 plus 2 plus root 2 multiplied by r3 and for r2 we will use as r2 minus 3 times of 3...