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Previous question 3 4 -3 -1 Let $y = \begin{bmatrix} 4 \ -6 \ 6 \end{bmatrix}$, $u_1 = \begin{bmatrix} -3 \ -4 \ 1 \end{bmatrix}$, $u_2 = \begin{bmatrix} -1 \ 2 \ 5 \end{bmatrix}$. Find the distance from y to the plane in $\mathbb{R}^3$ spanned by $u_1$ and $u_2$. The distance is $116\sqrt{\frac{1}{195}}$. (Type an exact answer, using radicals as needed.)

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Let $y = \begin{bmatrix} 4 \ -6 \ 6 \end{bmatrix}$, $u_1 = \begin{bmatrix} -3 \ -4 \ 1 \end{bmatrix}$, $u_2 = \begin{bmatrix} -1 \ 2 \ 5 \end{bmatrix}$. Find the distance from y to the plane in $\mathbb{R}^3$ spanned by $u_1$ and $u_2$.
The distance is $116\sqrt{\frac{1}{195}}$.
(Type an exact answer, using radicals as needed.)

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Previous question
3
4
-3
-1
Let y =
< b m a t r i x >, u1 =
< b m a t r i x >, u2 =
< b m a t r i x >. Find the distance from y to the plane in ℝ^3 spanned by u1 and u2.
The distance is 116√((1)/(195)).
(Type an exact answer, using radicals as needed.)

Added by Daniel M.

Calculus: Early Transcendentals

James Stewart 8th Edition

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Solved by Expert Eduard Sanchez

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To find the exact answer using radicals, we need to simplify the given distance of 116 195. Show more…

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Previous question _et y The distance is 116 195 Type an exact answer, using radicals as needed.

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