00:01
First of all, let's have a look what all is given in the problem.
00:05
Given is 4 octane is given, 4 octane.
00:13
And from 4 octane, we need to synthesize cis 4 octane.
00:17
Some of the compounds are given and we need to carry out the synthesis of those compounds.
00:23
So the first one that is given is we need to synthesize cis 4 octane from 4 octane.
00:36
Is our 4 octane and if it is treated with h2 in presence of pdba -h -o -4 in the presence of quinoline, then the product that will be formed will be cis 4 -octine.
00:55
Sys 4 -octine and this is our desired product.
01:00
The next one is we need to synthesize butanol from 4 octane.
01:05
We need to synthesize butanol from 4 octane.
01:09
So this is our four octane.
01:14
If it is treated with, again with palladium in presence of barium sulfate, in the presence of quinoline, then the compound formed will be cis -4 octane.
01:30
Sys4 -octine will be formed.
01:32
If it is undergone further ozonolysis, that is o3 in presence of zinc and h -2 -o -2, the compound formed will be butin al.
01:44
So this is our desired compound.
01:48
Next is we need to synthesize 4 bromobtain from 4 octane.
01:56
So let's draw the structure of 4 octane.
01:59
This is 4 octane and we need to synthesize 4 brommo octane.
02:10
So first of all, treat it with again palladium b .s .o .4 h2 in presence of quinoline.
02:17
It will form a cis 4 octane.
02:23
This is cis 4 octane...