Question

Problem #10: Find the range of the following function $f(x) = \begin{cases} \sqrt{-x} & x \le 0 \\ 3x + 1 & x > 0 \end{cases}$ (A) [-2,?) (B) (-?,?) (C) (-?, 1] (D) [0,?)

          Problem #10: Find the range of the following function
$f(x) = \begin{cases} \sqrt{-x} & x \le 0 \\ 3x + 1 & x > 0 \end{cases}$
(A) [-2,?) (B) (-?,?) (C) (-?, 1] (D) [0,?)

Problem #10: Find the range of the following function
f(x) = √(-x) x ≤ 0
3x + 1 x > 0
(A) [-2,?) (B) (-?,?) (C) (-?, 1] (D) [0,?)

Added by Lori D.

Calculus: Early Transcendentals

James Stewart 8th Edition

Instant Answer

Solved by Expert Benjamin Densmore

06/14/2022

Step 1

Step 1: The function f(x) is defined as f(x)={(\sqrt(-x),x<=0),(3x+1,x>0):} Show more…

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Problem # 10: Find the range of the following function f(x)={(sqrt(-x),x<=0),(3x+1,x>0):} (A) [-2,infty ) (B) (-infty ,infty ) (C) (-infty ,1] (D) [0,infty ) Problem # 10: Submit Problem #10 for Grading able[[ able[[Problem #10],[Your Answer:],[Your Mark:]],Attempt #1,Attempt #2,Attempt #3,Attempt #4]] Problem #10: Find the range of the following function 0> x f(x= 3x+1x> 0 (A[2,B)-0C-001]D)[0 Problem #10: Select Just Save Submit Problem #10 for Grading Problem #10 Attempt #1 Your Answer: Your Mark: Attempt #2 Attempt #3 Attempt #4