00:01
In this question, it is given to us magnetic field b equals to 2 .50 which is equal to 2 .50 multiplied by 10 r .2 to minus 3 tesla and the diameter of the loop is given diameter of loop which equals to of loop is equal to 1 .40 centimeter which is equal to 1 .40 multiply by 10 r .5x2 meter.
00:47
And in the first part of the question we need to find out what is the current in the loop.
00:55
In the first part we need to find the current in the load.
01:08
So the solution for this question is it refers to.
01:14
So that magnetic field due to a magnetic loop at center, b is equal to b is equals to mu not i divided by 2 r.
01:28
Where b is magnetic field, i is current, and r is the radius of the loop.
01:33
So when you put the above values in this formula, we get 2 .50 multiplied by 10 to power minus 3 is equals to 4 pi multiply by 10 raised 2 power minus 7.
01:51
Multiply by i which is we need to find out which is multiplied by 0 .7 and which is again multiply by 10 x to 5 minus 2 as we know diameter is equal to 2r so r is equal to d by 2 and d is given in a question which is 1 .4 so our i is comes out is i is equals to 27 .85 ampere this is the answer for our first part...