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Problem 7 (15 points) Fermat's little theorem states that if p is prime and a is an integer not divisible by p, then $a^{p-1} equiv 1 pmod{p}$. Use Fermat's little theorem to find $23^{1002} pmod{41}$. Note: Provide all details of your computation, including use of Fermat's little theorem! Provide your answer as a positive number, as small as possible.

          Problem 7 (15 points)
Fermat's little theorem states that if p is prime and a is an integer not divisible by p, then $a^{p-1} equiv 1 pmod{p}$.
Use Fermat's little theorem to find $23^{1002} pmod{41}$.
Note: Provide all details of your computation, including use of Fermat's little theorem! Provide your
answer as a positive number, as small as possible.
        
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Problem 7 (15 points)
Fermat's little theorem states that if p is prime and a is an integer not divisible by p, then a^p-1 equiv 1 pmodp.
Use Fermat's little theorem to find 23^1002 pmod41.
Note: Provide all details of your computation, including use of Fermat's little theorem! Provide your
answer as a positive number, as small as possible.

Added by Juan Francisco O.

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Calculus: Early Transcendentals
Calculus: Early Transcendentals
James Stewart 8th Edition
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Transcript

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00:01 Hello friends in this question by using firmitz little theorem we need to find 23 power 1 0 .002 at mode 41.
00:12 So now let p is equal to 41 and a is equal to 23.
00:21 Therefore p minus 1 is equal to 40 and therefore by fermits little theorem 23 power 40 is congruent to 1 mode 41 now by division algorithm we write 1002 is equal to 40 into 25 plus 2 therefore 23 power 1002 can be written as 23 40 into 25 plus 2 of more 41 so this is 23 power 40 into 25 of mode 41 now conformance little theorem says that if a is congruent to b of mode m then a power n is congruent to b power n of mode m for any positive integer n so since 23 power 40 is 1 with mode 41 it implies that 23 power 40 the whole power 25 is also 1 power 25 with mode 41.
02:36 So this implies that 23 power 40 into 25 is 1 of mode 41...
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