00:05
So part a is a joint pdf and of u and v.
00:29
So cdf of each variable f dash x x x plus 1 divided by 3 for minus 1 less than is equal to 2.
01:04
So f dash y so y is equal to y plus 1 divided by 3 for minus 1.
01:18
So let us calculate the joint cdf of u and v.
01:30
So joint cdf u and v.
01:38
How to calculate is f dash u v is equal to u comma v.
01:57
So is equal to p u less than greater than small u v small v.
02:08
So p minimum x y small u maximum x y.
02:25
So next one p p x u y small u.
02:56
So because minimum x and y is the same as a minimum x and y.
03:04
So then we write p x u p.
03:16
So due to independency of y and x and y.
03:23
So f dash x u multiplied by f dash y v.
03:32
So u plus 1 divided by 3 multiplied by v plus 1 divided by 3.
03:43
So these are equations.
03:48
Now we find the joint pdf.
03:52
So what's the joint pdf f is equal to u v and v both has u.
04:01
Find joint pdf.
04:10
So f dash u v small u v.
04:15
So is equal to 2 divided by u v.
04:24
So f dash u v u v.
04:35
So all are equal to 1 divided by 9.
04:39
So the given condition the joint pdf is 0 and u is less is greater than u and greater than v and greater than 2.
04:49
For the range of constant for choosing a total probability is equal to 1.
04:55
So the total so the total probability is equal to 1.
05:18
So so f dash u v d u d v is equal to 1.
05:32
The probability is equal to 1.
05:34
Integrate over the given condition integrating.
05:39
So this is a formula.
05:50
Then we change this is a condition of pdf.
05:54
So we integrate with so integrating over given range.
06:18
So what it is it is a c no already integrating we are now we solving now we solving the c.
06:38
So solving for c...