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Hello students.
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Today we will discuss about this question.
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In this question we are given that x be a random variable defined its probability density function that is fx of x that is equals to x if 0 x is less than 1, 2 minus x if 1 is less than x is less than 2 and 0 else.
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And we are given event a and b that can be defined as a that is equals to x is less than 1 and b that is equals to 1 divided by 2 is less than x is less than 3 divide by 2.
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And we need to show that a and b are independent event.
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So here for that event a that can be given as so here first of all we need to to find a and b.
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So that is equals to we will get 1 divided by 2 is less than x is less than 1 because the interval must be common in both events a and b.
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So therefore p of a that is equals to integration 0 to 1 fx of x d x that is equals to integration 0 to 1 x d x that is equals to x squared divided by 2 and the limit will be 0 to 1 so that is equals to 1 divided by 2 minus 0 so that is equals to 1 divide by 2 therefore p of a that is equals to half now we will find the p of b so that is equal to probability of 1 divide by 2 is less than x is less than 3 divided by 2 that is equals to integration 1 divide by 2 to 1 f x d x plus 1 2 2 2 2 of x d x plus 1 2 2 2, 3 divided by 2, fx of x d x.
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So that is equals to integration 1 divided by 2 to 1 x d x plus integration 1 to 3 divide by 2 minus x d x.
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So that is equals to x squared divide by 2 limit will be minus 1 by 2 to 1 plus 2x minus x square divide by 2, limit will be 1, 2 3 divided by 2...