00:02
Okay, so now we have a problem where we have a spring attached to a ceiling and we're going to hang a mass from it and when that mass is equal to two kilograms we get a stretch length of 15 centimeters again every time they give a centimeters.
00:21
Let's just convert it to meters.
00:22
0 .15 meters and the question is what is the spring constant? so this is a newton's second lie equation sigma f is equal to m a i'm going to draw a free body diagram that for this mass i've got a force of spring pulling upward that should be an s force of spring pulling upward and i've got a force of gravity pulling downward and so my forces are my let's go ahead and just say up is positive so f s minus fg is equal to my mass times acceleration but if i'm just hanging it from there, that acceleration is equal to zero.
01:08
And so i've got fs is equal to fg.
01:11
And my fs is just k times x.
01:15
My fg is just m times g.
01:19
And so again, i said this in an earlier video.
01:24
Be very, very careful with this equation.
01:26
Sometimes there's a minus sign associated with it.
01:28
All that minus sign tells you is which direction to draw the arrow.
01:32
We know the spring's pulling up, we've got no business having that minus sign in the mix.
01:37
And so i'm solving for k.
01:39
K is going to equal to mg divided by x.
01:42
I know my mass is 2.
01:44
I know my g is 9 .8.
01:47
I know my g is 0 .15.
01:50
And we're going to plug that into our calculator.
01:55
9 .8 times 2 divided by 0 .15.
01:59
That's 130 point a whole bunch of sixes...