Problem 5. Compute the following (a) $\int \frac{e^{2x}}{\sqrt{e^{2x}+3}} dx$ (b) $\int \frac{e^{4x}+e^{x}}{e^{2x}} dx$ (c) $\int_{1}^{3} t^{-4/5} e^{t^{1/5}} dt$
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Then $du = 2e^{2x} dx$, so $e^{2x} dx = \frac{1}{2} du$. The integral becomes $\int \frac{e^{2x}}{\sqrt{e^{2x}+3}} dx = \int \frac{1}{\sqrt{u}} \frac{1}{2} du = \frac{1}{2} \int u^{-1/2} du = \frac{1}{2} \frac{u^{1/2}}{1/2} + C = u^{1/2} + C = \sqrt{e^{2x}+3} + Show more…
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