Problem 5. Let \( f(x)=m x+b \) be a linear function on \( \mathbb{R} \). Show \[ |f(x)-f(y)|=|m||x-y| \] for all \( x, y \in \mathbb{R} \). Thus linear functions are Lipschitz on all of \( \mathbb{R} \).
Added by Cassie M.
Close
Step 1
Step 1: Start with the given linear function \( f(x) = mx + b \). Show more…
Show all steps
Your feedback will help us improve your experience
Likhit Ganedi and 58 other Calculus 3 educators are ready to help you.
Ask a new question
Labs
Want to see this concept in action?
Explore this concept interactively to see how it behaves as you change inputs.
Key Concepts
Recommended Videos
Prove that if $\left|f^{\prime}(x)\right| \leq M$ for all $x$ in $(a, b)$ and if $x_{1}$ and $x_{2}$ are any two points in $(a, b)$ then $$\left|f\left(x_{2}\right)-f\left(x_{1}\right)\right| \leq M\left|x_{2}-x_{1}\right|$$ Note: A function satisfying the above inequality is said to satisfy a Lipschitz condition with constant $M$. (Rudolph Lipschitz $(1832-1903)$ was a German mathematician.)
Applications of the Derivative
The Mean Value Theorem for Derivatives
Prove that f(x) = 1/x is uniformly continuous on any interval (a, ∞) with a > 0.
Sri K.
Use the $\epsilon-\delta$ definition of a limit to prove that the linear function $f(x)=a x+b$ is continuous everywhere.
Limits and Continuity
The $\varepsilon-\delta$ Definition of Limit
Recommended Textbooks
Calculus: Early Transcendentals
Thomas Calculus
18,000,000+
Students on Numerade
Trusted by students at 8,000+ universities
Watch the video solution with this free unlock.
EMAIL
PASSWORD