00:02
Y is equal to w0 by 120 ei l minus x to the power 5 plus 2 l square x cube minus l4 x.
00:18
Now differentiating it with respect to x we will get the value as w0 by 120 ei l.
00:28
We will get as minus 5 x to the power 4 plus 6 l square x to the power 2 minus l to the power 4.
00:37
Equating it to 0 we will get two values of x as x equals to 3, 2 and x equals to 0.
00:47
As we have the value of l as 600 cm and now we will substitute the value of x and two values of x, y of 2 as minus 5.
01:02
Here we have value of e as 50000 kn 50 ,000 kn per cm square, i as 30000 cm power 4 and w0 as 2 .5 kn per cm.
01:31
And substituting everything we will get the value as minus 5 x 2 to the power 4 plus here we will have 216 x 2 to the power 2 minus 1290.
01:46
Here we are taking the values of y dash of 2 and here we will get the value as minus 512.
01:56
Now similarly we will solve it as 3.
01:59
We will get as minus 5 x 2 to the power 4 plus 216 x 3 to the power 2 minus 1290.
02:07
The value will be 243.
02:10
As f dash of 2 is less than 0 and f dash of 3 is greater than 0 the point of convergence will be somewhere between the the root will lie in between 2 or 3.
02:24
So we will find the value of root as x dash or x1 equals to 2 plus 3 by 2.
02:34
From here we will get the value as 2 .5 by 2 which is equal to 2 .5.
02:41
Now we will take consider the value 2 .5 and we substitute it and we will get the value as 2 .5 to the power 4 plus 216 x 2 .5 to the power 2 minus 1290.
02:57
So we will get the value as minus 141 .3...