00:01
So here we have to determine the force in the member df, ef and eg which is shown here in this figure.
00:09
So this is the given figure.
00:14
So this is the given figure.
00:16
Let's say here is point h, here is point g.
00:19
From here it is point f, this is point e, this is point d, this is point c, this is point b and this is point a.
00:33
So this is point a.
00:38
So this is the value from here and in this side we are having g, i, j, k, l, m and n.
00:54
From here, from point n a force of 16 kilo newton is acting in this direction and from here to again a 16 kilo newton force is acting and the distance between all them is 3 meters.
01:06
So here we are considering this term.
01:09
So theta is equals to tangent inverse of 4 divided by 3 in this case that become equals to 53 .13 degree.
01:15
Now summation over ma is equals to 0.
01:18
So minus of ny which is multiplied by the 24 is equals to 0.
01:22
So ny is equals to 0 in this case and summation of fy is equals to 0 which means ay is equals to 0 and summation of f of x is equals to 0 which means ax is equals to 16 minus 16 that is equals to 0.
01:36
Now we are considering about the point a.
01:39
So for a, summation of f of x is equals to 0.
01:43
So 16 plus r of ac multiplied by the sin of 53 .13 that is equals to 0...