00:01
So, for this question to solve for the draft d, bf will be equal to w and we know that here we have 9 .81 kn divided by m3.
00:14
This will be basically multiplied by 10 m, this multiplied by 30 m and it will be multiplied by d because this vd will be equal to w.
00:27
So, from this it will be equal to 4500 kn and d is equal to 1 .53 m.
00:35
Now distance from d to center of buoyancy that is gbo will be equal to 4 m minus d divided by 2 which will be equal to 4 m minus 1 .53 m divided by 2 which will be equal to 3 .24 m.
00:56
Now along the longitudinal axis which is along the longitudinal axis we will take which is basically rolling.
01:14
So, here we will take b is equal to 10 m.
01:18
Now we know that mbo will be equal to b square divided by 12 d.
01:25
In the bracket we have 1 plus 10 square theta divided by 2 and this is where theta is equal to 0 degree.
01:35
We will substitute the value.
01:36
So, this will be 10 m whole square divided by this is 12 which is multiplied by d that is 1 .53 and this in bracket we have 1 plus 0.
01:48
From this it will be equal to 5 .45 m.
01:52
Now mg will be equal to 5 .45 will be subtracted by 3 .24 which will be equal to 2 .21 m...