00:01
Hi, in this question we have to give the shear diagram and bending diagram for the given problem.
00:05
So, here we are given with this question.
00:07
So, here we have this is so here it is a moment applied is 4 feet second.
00:13
So, this is 12 k kps and this is 20.
00:16
So, this is the force acting ay and this is the force acting along rd.
00:23
So, here we have so here we have taking moment along point o.
00:28
So, here we have 20 into 6 plus 12 into 14 plus 12 into 28 minus rd into 24 is equal to 0.
00:39
So, from this we can take the value of rd is equal to 26 kps and also we have ay plus rd is equal to 20 plus 12 plus 12 which is equal to 18 kps that is ay.
00:56
So, now we have the bending diagram and the shear moment diagram is given by.
01:02
So, here we have this is the point a, point b, c, d and e.
01:08
So, here we have from point a to point b then to point c, c to d and then we have d to e.
01:22
So, here we have it is 18 kps which is the force ay which we have calculated.
01:28
Again here we have 18 kps because we have 20 kps forces acting.
01:35
Then here we have minus 2 kps again here minus 2 kps and we have so this is the force minus 14 kps.
01:46
Then we have about this point it is 12 kps...