Question

Q\\ Pi = 4000 Psi, Pb = 3000 Psi, Pwf = 2000 Psi\\ Find: ? ?\\ ? J?\\ ? J?max\\ ? J? @ Pwf = 3500\\ ? J? @ Pwf = 1000\\ Plot IPR curve\\ P_{wf} < P_b^2\\ 1) ? = \frac{2}{P_i - P_b + \frac{P_b}{1.8} [1 - 0.2(\frac{P_{wf}}{P_b}) - 0.8(\frac{P_{wf}}{P_b})^2]}\\ 2) J_b = J(P_i - P_b)\\ 3) J_0 = J_b + \frac{J_b}{1.8} [1 - 0.2(\frac{P_{wf}}{P_b}) - 0.8(\frac{P_{wf}}{P_b})^2]

          Q\\
Pi = 4000 Psi, Pb = 3000 Psi, Pwf = 2000 Psi\\
Find: ? ?\\
? J?\\
? J?max\\
? J? @ Pwf = 3500\\
? J? @ Pwf = 1000\\
Plot IPR curve\\
P_{wf} < P_b^2\\
1) ? = \frac{2}{P_i - P_b + \frac{P_b}{1.8} [1 - 0.2(\frac{P_{wf}}{P_b}) - 0.8(\frac{P_{wf}}{P_b})^2]}\\
2) J_b = J(P_i - P_b)\\
3) J_0 = J_b + \frac{J_b}{1.8} [1 - 0.2(\frac{P_{wf}}{P_b}) - 0.8(\frac{P_{wf}}{P_b})^2]

Q

Pi = 4000 Psi, Pb = 3000 Psi, Pwf = 2000 Psi

Find: ? ?

? J?

? J?max

? J? @ Pwf = 3500

? J? @ Pwf = 1000

Plot IPR curve

Pwf < Pb^2

1) ? = (2)/(Pi - Pb + (Pb)/(1.8) [1 - 0.2((Pwf)/(Pb)) - 0.8((Pwf)/(Pb))^2])

2) Jb = J(Pi - Pb)

3) J0 = Jb + (Jb)/(1.8) [1 - 0.2((Pwf)/(Pb)) - 0.8((Pwf)/(Pb))^2]

Added by Anita M.

Chemistry: Structure and Properties

Nivaldo Tro 2nd Edition

Instant Answer

Solved by Expert Sri K

06/14/2023

Step 1

Step 1: First, let's identify the given values: P = 400 PSI Pb = 30 PSI PP = 200 PSI Show more…

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Production engineering solves the question with these formulas: P = 400 PSI Pb = 30 PSI PP = 200 PSI Find @% Pf < Rb2 GJomar 2 Pf - 35 P - R[1--] 2)J(Pf O80Rf - 1 36 + [1-0-0] PLt - IPR Curve