00:01
Hi, today we are solving the question in which first we need to consider the systematic error of 0 -0 .1v.
00:11
This means that the actual signal sent by the detector when it detects motion is actual signal is equals to 5 -0 .1 it is equals to 4 .9v.
00:29
Next we need to consider the random noise.
00:32
The noise has a normal distribution with a mean of 0 .0.
00:37
So mean is 0 .0 and standard deviation is 0 .4.
00:42
So this means that the actual signal received by the controller can be anywhere from 4 .9 actual signal can be taken as 4 .9 -0 .4.
01:00
So we get it as 4 .5v.
01:07
4 .9 plus 0 .4 so it is equals to 5 .3v.
01:16
So we can say actual signal will be from 4 .5v to 5 .3v.
01:30
Now the controller will only assume unauthorized presence if it receives a signal that is more than 4 .5v.
01:48
So therefore the probability that a break -in will not be detected is the probability that the signal received by the controller is less than or equal to 4 .5v.
02:00
So to calculate this probability we would need to standardize the value of 4 .5v.
02:07
So from here using the z -score it is taken as z is equals to x -mu divided by sigma where x is the value mu is the mean and sigma is the standard deviation.
02:20
Now here we can substitute 4 .5 -4 .9 divided by 0 .4...