00:01
Dear students, two half reactions are given here and the condition is acidic medium.
00:07
So we have to balance the each half reaction and we have to write the complete reaction.
00:12
Now let us start with the first one.
00:14
Let us check the oxidation states.
00:17
Here 3 -2 -4 -6, 2 minus means 4 plus, sulfur as 4 plus means sulfur as 2 plus here.
00:26
So here 6 units, negative charge, 6 atoms of oxygen means, 6, 2x12, 2 minus means 10, minus 10, so here each sulfur has 2 .5 plus there is increase in oxidation state, therefore this is oxidation half reaction.
00:46
Now the second part is reduction half reaction clearly.
00:50
Here i3 minus.
00:54
Now i3 minus means here minus 1 third and here minus 1.
00:59
That means here reduction of oxidation number is decreased, therefore this is reduction half a reaction.
01:11
Now start first, let us start the balancing the first one.
01:15
Here four sulfur atoms, here two sulfur atoms, let us put here two.
01:23
Now each sulfur atom has caused a decrease in an increase in oxidation number of 0 .5, so falls four sulfur atoms plus two in its then.
01:35
So we need to two electrons.
01:38
Now oxygen here 6, here 6, oxygen is balanced...