00:01
Question is proposed structures of aromatic hydrocarbons that meet the following descriptions.
00:05
So first the c9h12 gives only one c9h11 br product on the substitution of a hydrogen atom on the aromatic ring with bromine.
00:17
Okay, so we are going to discuss what is the structure of the c9h12 compound that will give only one product on the substitution of the benzging ring.
00:30
Right so first we have to identify what is the degree of unsaturation of the c9 h12 so the degree of unsaturation of the c9 h12 is the 4 that means we can say that 4 means it must have one bengen ring or 3 pi bound or 2 pi bound 2 ring so we can say that it should be benzene ring because benzene ring is the aromatic ring and we can imagine that aromatic ring like as benzene ring right so benzene ring is the c6 h5 so we have to add three more carbon to form c9 h 12 so how can we add 3 carbon so that we can get only one substrate one product suppose if we add propite ch2, ch2, ch3.
01:29
And we will take br2 in the presence of fe, then we can get two products.
01:37
One is here and two is here, right? so it is not requirement.
01:43
So we will add three carbons like this, ch3, ch3, and cs3.
01:53
So this compound have molecular formula c9h12.
01:58
Now this compound is reacting with the br2 fe.
02:02
Then br2 can add only at this position, this position and this position.
02:08
So these three positions are the symmetric with respect to each methyl group.
02:14
Suppose if we add bromine here, correct.
02:22
So what is the iupc name of this compound? 1, 2, 3, 4, 5, 6.
02:30
So 2 .4 .6 tri -methal bromobenzion.
02:36
If we add bromine group, bromine group here, correct.
02:44
So iupc name will be what? iopc name will be what? 1, 2, 3, 4, 5, 6.
02:57
So 2 .4 .6 tri -methyl bromogen...