00:01
We are given with the order of group.
00:05
Order of group is given as 6 1 6.
00:11
If we write its prime decomposition, it become 2 power 3, 7 power 1 and 11 power 1.
00:22
There are two silos subgroup of order 8 are possible either 1 or either 1 group or 7 groups.
00:39
Now it is 7.
00:43
7 silos subgroup of order 7 that are possible either 1 or 8.
00:55
Now 11 silos subgroup of order 11 that possibilities are 1 or 56.
01:10
So if this group is not simple that mean there will be another simple group.
01:17
We are choosing there that we are not getting simple group from his.
01:22
That mean we are getting 8 subgroups of 7 silos subgroup and we are getting 56 11 silos subgroup.
01:31
We are using the formula for finding the number of elements.
01:35
Here is number of subgroups for prime order.
01:42
Subgroups is equals to number of elements of that order divide with 5 of that order 5 of that number...
