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In this question we are asked to prove the following properties of boulogne algebra.
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So let's start to solve this problem.
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We know in boulogne algebra the value of any variable is either 0 or 1.
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Suppose we have two variables a and b.
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So here the value of a is either 0 or 1 and here the value of b is also either 0 or 1.
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Here to solve this problem we use following formulas.
00:26
First one, a plus a bar is zero.
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Equals to why? suppose if a equals to 0 then we obtain 0 plus 0 bar equals to 1 equals to 1.
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And suppose if a is equal to 1, then we obtain 1 plus 0 is also equal to 1.
00:47
That means for any variable a, a plus a bar is always equal to 1.
00:54
Second one, a into a bar is equal to 0.
01:00
Because if a equals to 0 then a bar is equal to 1, then 0 into 1 becomes equal to 0.
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And suppose if a equals to 1, then 1 into 0 is also becomes equal to 0.
01:11
3 1 plus a is equal to 1.
01:15
Or 1 plus a bar is equal to 1...