Python 3 write a function def mydatetimenumsec this function...

PYTHON 3: Write a function def my_datetime(num_sec). This function takes in an integer value that represents the number of seconds since the epoch: January 1st, 1970. The function takes num_sec and converts it to a date and returns it as a string with the following format: MM-DD-YYYY. It has the following specifications: - It may be assumed that num_sec will always be an int value. - It may be assumed that num_sec will always be a positive value. - Must be able to handle leap years. Some examples: - my_datetime(0) returns 01-01-1970. - my_datetime(123456789) returns 11-29-1973. - my_datetime(9876543210) returns 12-22-2282. Your function handles all the computation itself. You are not permitted to use any library that can convert seconds to a date. This includes, but is not limited to: datetime, arrow, moment, maya, delorean, freezegun.

Transcript

00:01 In this question, the question asks for implementation of function called mydatetime.

00:07 So we have to create this function mydatetime.

00:15 Then what we have to do is, this function should take an integer representing the number of seconds since january 1st, 1970 and converts it to a date string in format mmddyy.

00:36 Why? the function should be able to handle leap years.

00:48 Then it should perform all necessary computation without relying on external libraries.

00:54 It provides example of expected inputs and outputs, demonstrating the desired behavior of the function without any external libraries.

01:16 Let's create this function and see the code for it which satisfies all these conditions.

01:24 So we are in google colab and let's make our datetime function.

01:35 So what we'll do is, first we will define the function like this and we will pass num underscore second as a parameter in it.

01:46 Then we will make a variable seconds in a day.

01:53 So 24 x 60 x 60.

01:58 So when we multiply 24, 60 and 60, we will get the total number of seconds in a day.

02:04 Then we have to find one more parameter that is number of days.

02:12 So we'll create a variable numdays and let it be number of seconds divided by seconds in a day.

02:23 Then startdate january 1st, 1970.

02:34 For that we will declare another three variables like this.

02:48 So then we will run a while loop by writing while true.

02:56 So what it will do is it will start the while loop from the first instance.

03:04 Now we will create a variable called days in a year.

03:09 So we have mentioned 365.

03:14 Then we'll check if year modulus 4 is equal to equal to 0 like this and year modulus of 100 is not equal to 0 or year modulus of 400 is equal to equal to 0.

03:37 Then we have to overwrite this days in year as 366 means what we are doing is we are handling the condition of a leap year here.

03:50 So if this condition checks that this is a leap year, then we will update our days in year variable with 366.

04:00 Now if number of days are less than days in year like this, then what we will do is we will break this for loop.

04:28 Now if this is not true, if number of days are not less than in a year, it will not come out of for loop here and it will run the following two other lines followed by this statement.

04:50 So what it will do is it will perform number of days, days in year.

04:57 It is counting the days and decreasing the days from this year.

05:03 So number of days equal to number of days minus days in year...

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